The magnetic field inside an air-filled solenoid 35 cm long and 2.4 cm in diameter is 0.71 T . Approximately how much energy is stored in this field?
Added by Francisco Jose V.
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71\) T and \(\mu_0 = 4\pi \times 10^{-7}\) Tm/A. Plugging in the values, we get: \[E_V = \frac{(0.71)^2}{2 \times 4\pi \times 10^{-7}} = 2.0575 \times 10^7 \text{ J/m}^3\] Show more…
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