the mass of the Na2CO3 product is 5.68 g The molar mass of Na2CO3 is 105.99 g/mol THe molar mass of NaHCO3 is 84.01 g/mol What is the mass of the initial amount of NaHCO3?
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\[ \text{Moles of Na2CO3} = \frac{\text{mass of Na2CO3}}{\text{molar mass of Na2CO3}} = \frac{5.68 \, \text{g}}{105.99 \, \text{g/mol}} \approx 0.0536 \, \text{mol} \] Show more…
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What mass of NaHCO3 must have been present at the beginning of the reaction? Assume the reaction is: 2NaHCO3 -> Na2CO3 + CO2 + H2O Hint: Your goal is to do the steps you did in the previous section, but in reverse. You know the mass of the Na2CO3 product is 5.09g. The molar mass of Na2CO3 is 105.99g/mol. The molar mass of NaHCO3 is 84.01g/mol. How can you use this information to find the mass of the initial amount of NaHCO3?
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