00:01
We have mass times yodal prime plus a plus f plus b times y prime plus k times one to equal omega t.
00:34
For pretty resolving using big y e.
00:41
A cosine omega t, bcite, bcate, omega, t.
00:53
Y prime of t is equal to minus a omega, sine, omega, t plus b, omega, omega, omega, omega, t.
01:17
Which is equal to minus a, omega, square, cosine omega plus e omega square sine omega t insert into the below and you're able to get a minus x times omega square times cosine cosine omega k plus of e times x times omega square cosine omega square multiply by sine omega t plus b times little b times cosine omega t minus a times omega of omega omega omega t.
03:14
Solve the equations, the equation you produce are a times k minus m, omega square, plus big a, little b, omega, omega, equal 1, e times k minus m times omega square, minus a 10 little b omega equal zero and the answer to produce is going to be a fccccule you'll get k minus m times omega squared divide a 5 k minus m times omega square plus b squared and b ab equal a little b omega square it's omega divided up k minus m times omega squared multiple squared year pose little b times omega square times omega square following that you for part b you use it a graph this equation is b 0 .1 and mass 0 .1 and k is the name.
04:49
So you place the functions in.
04:52
First you got to do the a equal to using the values that you replace it with above here will be 25 minus omega squared divided by minus omega squared 0 .01 mega squared with b equal 0 .1 omega multiplied by 25 times omega squared plus 0 .01 omega square.
05:34
So then you got to plot the graph.
05:40
So here it is.
05:41
First you have you have omega here on the x -axis and the other one.
05:47
It's either a r b.
05:48
So at 5, when omega equals 5, it's going to be undefined.
05:55
So it's almost as you go from the left side, go to the left, it will be going to zero...