The matrix \begin{equation*} A = \begin{bmatrix} 0 & 0 & 0\\ -3 & 3 & 0\\ 3 & -3 & 0 \end{bmatrix} \end{equation*} has two real eigenvalues, one of multiplicity 1 and one of multiplicity 2. Find the eigenvalues and a basis for each eigenspace. The eigenvalue $\lambda_1$ is and a basis for its associated eigenspace is The eigenvalue $\lambda_2$ is and a basis for its associated eigenspace is
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The characteristic equation is: \[ \det \begin{bmatrix} -\lambda & 3 \\ 3 & -3-\lambda \end{bmatrix} = 0 \] Expanding the determinant, we get: \[ (-\lambda)(-3-\lambda) - 3(3) = 0 \] \[ \lambda^2 + 3\lambda - 9 = 0 \] Using the quadratic formula, we find the Show more…
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