Question

The mean and the standard deviation for the discrete uniform distribution: Suppose X is a discrete uniform random variable on the consecutive integers a, a + 1, a + 2, ... b for a ? b, then 1. The mean: ? = E(X) = (b+a)/2 2. The variance: ?^2 = ((b-a+1)^2 - 1)/12

          The mean and the standard deviation for the discrete uniform distribution:
Suppose X is a discrete uniform random variable on the consecutive integers
a, a + 1, a + 2, ... b for a ? b, then
1. The mean: ? = E(X) = (b+a)/2
2. The variance: ?^2 = ((b-a+1)^2 - 1)/12

The mean and the standard deviation for the discrete uniform distribution:
Suppose X is a discrete uniform random variable on the consecutive integers
a, a + 1, a + 2, ... b for a ? b, then
1. The mean: ? = E(X) = (b+a)/2
2. The variance: ?^2 = ((b-a+1)^2 - 1)/12

Added by Milagros M.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert Lucas Finney

09/30/2022

Step 1

It is a type of probability distribution in which all outcomes are equally likely. In this case, the outcomes are the consecutive integers from a to b. The mean (μ) of a distribution is its expected value. For a discrete uniform distribution, every outcome is Show more…

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The mean and the standard deviation for the discrete uniform distribution: Suppose X is a discrete uniform random variable on the consecutive integers a, a + 1, a + 2, ..., b for a ≤ b. Then, the mean (μ) is given by μ = (b + a) / 2 and the variance (σ^2) is given by σ^2 = ((b - a + 1)^2 - 1) / 12.