The mean score for a test was 81.52 with a standard deviation of 9.2. The scores are normally distributed. If a person is selected at random find that the probability that his/her score was: (Round to the nearest 1000th ) a. Less than 75 b. Between 85 and 92 b. More than 95 c. If 28 students took the test, how many scored more than a 95 (round to the nearest whole number)
Added by Lauren M.
Step 1
Step 1: Calculate the z-score for each given score using the formula: z = (X - μ) / σ, where X is the score, μ is the mean, and σ is the standard deviation. Show more…
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Donya D.
The mean score for a test was 81.52 with a standard deviation of 9.2. The scores are normally distributed. If a person is selected at random find that the probability that his/her score was: (Round to the nearest 1000th ) a. Less than 75 b. Between 85 and 92 c. More than 95 d. If 28 students took the test, how many scored more than a 95 (round to the nearest whole number)
Willis J.
On a certain test, a mean test score μ is 82 and a standard deviation σ is 12. Assume that test scores are normally distributed. (Round to four decimal places as needed) a.) If 1 student is randomly selected, find the probability that his/her score is less than 85. b.) If 30 students are randomly selected, find the probability that they have a mean score less than 85.
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