5. The mean weight for adult males is 158.1 pounds, with a standard deviation of 22.0 pounds, distributed normally. Let x represent the weight of a randomly selected adult male. Compute the following probabilities: a. P(x > 180) = b. P(171 < x < 190) = 6. Using the mean and standard deviation for adult male weights from the previous problem, what weight represents, approximately, the 92nd percentile?
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P(x > 180): We need to find the area to the right of 180 on the normal distribution curve. We can use a standard normal distribution table or a calculator to find this probability. Using a calculator, we can use the formula: P(x > 180) = 1 - P(z < (180-158.1)/22) Show more…
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