The minimum work which must be done to compress 0.1 moles of an ideal gas isothermally (at 727°C), from 1.04 × 10^4 N/m^2 to 1.04 × 10^6 N/m^2, is: [ln 10 = 2.3, R = 8.3 J/K-mol] A. 3181 J B. 3818 J C. 821.7 J D. 830 J
Added by Theresa K.
Step 1
- Number of moles, n = 0.1 moles - Initial pressure, P1 = 1.04 × 10^4 N/m² - Final pressure, P2 = 1.04 × 10^6 N/m² - Temperature, T = 727°C = 727 + 273 = 1000 K - Universal gas constant, R = 8.3 J/K-mol The work done on an ideal gas during isothermal compression Show more…
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