The molar mass of HF is 20.01 g/mol. How many moles of Sn are required to react with 40 g of HF?
Added by Nancy H.
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First, we need to find the number of moles of HF in 40 g. Show more…
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Mass-Mole Stoichiometry mass of given → moles of given → moles of unknown How to Perform Mass-Mole Stoichiometry Calculations Sn(s) + 2HF(g) → SnF2(s) + H2(g) How many moles of HF are required to react completely with 128 g of Sn? (previous example) 75.0 g Sn x 1 mol Sn / 118.69 g Sn x 2 mol HF / 1 mol Sn = 1.26 mol HF
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