The molecular weight of vincristine, a pharmaceutical drug, is 923.04 g/mol. It is supplied in 1 mg per vial. You want to treat your culture cells with a final concentration of 7 nM vincristine and will need 12 mL of cells for your experiment. You only want to add 21 µL of vincristine solution to your cells. What concentration should you make your stock solution of vincristine in order to make this 21 µL addition?
Added by Allison S.
Step 1
Given that the final concentration is 7 nM and the volume of cells is 12 mL: Number of moles = Concentration x Volume Number of moles = 7 x 10^-9 mol/L x 0.012 L Number of moles = 8.4 x 10^-11 mol ** Show more…
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The molecular weight of vincristine, a pharmaceutical drug, is 923.04 g/mol. It is supplied in 1 mg per vial. You want to treat your culture cells with a final concentration of 7 μM vincristine and will need 12 mL of cells for your experiment. You only want to add 21 μL of vincristine solution to your cells. What concentration should you make your stock solution of vincristine in order to make this 21 μL addition?
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