The net force exerted on a particle acts in the +x direction. Its magnitude increases linearly from zero at x=0.0 to 24.0 N at x=3.0 m. It remains constant at 24.0 N from x = 3.0 m to x = 7 m, then decreases linearly to zero at x=13.0 m. Determine the work done in joules to move a particle from x=0 to x = 13 m. A) 408 B) 204 C) 96 D) 72 E) 36
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In this case, the force varies with position, so we will need to calculate the work done over each section where the force behaves differently. Show more…
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(II) The net force exerted on a particle acts in the $+x$ direction. Its magnitude increases linearly from zero at $x=0$ , to 24.0 $\mathrm{N}$ at $x=3.0 \mathrm{m}$ . It remains constant at 24.0 $\mathrm{N}$ from $x=3.0 \mathrm{m}$ to $x=8.0 \mathrm{m}$ , and then decreases linearly to zero at $x=13.0 \mathrm{m}$ . Determine the work done to move the particle from $x=0$ to $x=13.0 \mathrm{m}$ graphically by determining the area under the $F_{x}$ vs. $x$ graph.
(II) The net force exerted on a particle acts in the positive $x$ direction. Its magnitude increases linearly from zero at $x = 0 ,$ to 380$\mathrm { N }$ at $x = 3.0 \mathrm { m }$ . It remains constant at 380$\mathrm { N }$ from $x = 3.0 \mathrm { m }$ to $x = 7.0 \mathrm { m } ,$ and then decreases linearly to zero at $x = 12.0 \mathrm { m } .$ Determine the work done to move the particle from $x = 0$ to $x = 12.0 \mathrm { m }$ graphically, by determining the area under the $F _ { x }$ versus $x$ graph.
The force acting on a particle varies as in Figure P5.59. Find the work done by the force as the particle moves (a) from $x=0$ to $x=8.00 \mathrm{m},(\mathrm{b})$ from $x=8.00 \mathrm{m}$ to $x=10.0 \mathrm{m},$ and $(\mathrm{c})$ from $x=0$ to $x=10.0 \mathrm{m} .$
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