The normal boiling temperature of chloroform is 61.7 oC, its molar enthalpy change of vaporization is 29.5 kJ/mol. Estimate the vapor pressure of chloroform at 50.0 oC
Added by Michael S.
Step 1
0 °C. The equation is: ln(P2/P1) = -(ΔHvap/R)(1/T2 - 1/T1) where P1 and P2 are the vapor pressures at temperatures T1 and T2, respectively, ΔHvap is the molar enthalpy change of vaporization, and R is the ideal gas constant (8.314 J/mol·K). Show more…
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