00:01
In this question it is given that there is a bar like this and several forces are acting on this bar.
00:16
This is point o and this force is f x and this force is f y.
00:39
This force is ry and this force is r x.
01:00
The gravitational force is acting from the midpoint f, g.
01:08
The total length of the bar is l and this angle is 3 -ta.
01:21
Now we have to find the equation which represents the sum of tors acting on this object since the object is in rotational equilibrium so the sum of all the torques on this object should be equal to 0 the sum of all the tors on this object should be equal to zero because it is in rotational equilibrium so let us write the equation of net torque net torque on this object is equal to zero net torque as we can see that ry and rx are passing from the x's point o, so they will produce no torque.
02:10
Ry and rx will produce zero torque because they are passing from the axis.
02:16
Only the gravitational force and fy and fx will produce the torque.
02:22
So first of all, the fy force will produce a torque.
02:32
Positive torque is the anticloquoise direction.
02:36
Let the anti -clockwise direction is the positive...