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14. The oligopeptide hepcidin is a ligand for the receptor-gated channel ferroportin that is critical for the absorption of dietary iron (III) in the small intestines. Why does your body need a channel (which is a protein that forms an aqueous pore across lipid membranes for iron (III) to transverse the lipid membrane?

          14. The oligopeptide hepcidin is a ligand for the receptor-gated channel ferroportin that is critical for the absorption of dietary iron (III) in the small intestines. Why does your body need a channel (which is a protein that forms an aqueous pore across lipid membranes for iron (III) to transverse the lipid membrane?
        
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14. The oligopeptide hepcidin is a ligand for the receptor-gated channel ferroportin that is critical for the absorption of dietary iron (III) in the small intestines. Why does your body need a channel (which is a protein that forms an aqueous pore across lipid membranes for iron (III) to transverse the lipid membrane?

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Biology for AP Courses
Biology for AP Courses
Julianne Zedalis, John Eggebrecht
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The oligopeptide hepcidin is a ligand for the receptor-gated channel ferroportin that is critical for the absorption of dietary iron (III) in the small intestines. Why does your body need a channel (which is a protein that forms an aqueous pore across lipid membranes) for iron (III) to transverse the lipid membrane? A channel is needed 14.The oligopeptide hepcidin is a ligand for the receptor-gated channel ferroportin that is critical for the absorption of dietary iron (IIl) in the small intestines.Why does your body need a channel(which is a protein that forms an aqueous pore across lipid membranes for iron(Ill) to transverse the lipid membrane? A channel is needed
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Transcript

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00:01 In the question we are given that, chloroenyl methoxycarbonil group is used to protect the amino group in, the amino group in merrifield solid phase in merrifield solid phase peptide synthesis.
01:21 And we are asked here to show the required mechanism, and the final product.
01:41 So here is what happening.
02:22 Here there is oxygen and then there is around o c .a.
02:37 And this is reacting with this.
03:06 This is reacting with this.
03:10 Now this lone pair, it will attack this carbon and it will go on the oxygen.
03:21 And the product which will be formed and here what will happen this minus charge again coming back here and cl minus is getting deducted from here and the hydrogen here coming back to the coming back to its place on the plus charge so after this rearrangement there will be a stable product and there will be a plus charge here now this will be attacked by by this pdine so this n will attack here the hydrogen available here and the possible product here will be what and here there will be a minus charge and this will be the product now this minus charge we go here and this one will open on the oxygen and hence there will be two products formed and the two products will be this will be one product and another one will be here there will be r and here will be the minus charge okay now this minus charge on coming here this bond will shift on nitrogen...
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