Question

The one-to-one function g is defined below. g(x) = (9x-1) / (5x+9) Find g^-1(x), where g^-1 is the inverse of g. Also state the domain and range of g^-1 in interval notation. g^-1(x) = Domain of g^-1 : Range of g^-1 :

          The one-to-one function g is defined below.
g(x) = (9x-1) / (5x+9)
Find g^-1(x), where g^-1 is the inverse of g.
Also state the domain and range of g^-1 in interval notation.
g^-1(x) =
Domain of g^-1 :
Range of g^-1 :

Added by Sierra L.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Ahmet Yavas

04/28/2022

Step 1

Let g(x) = y, then we have y = 9x - 5. To find the inverse, we switch x and y and solve for y: x = 9y - 5 x + 5 = 9y y = (x + 5) / 9 Therefore, the inverse function g^(-1)(x) = (x + 5) / 9. ** Show more…

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The one-to-one function g is defined below. g(x) = (9x - 1) / (5x + 9) Find g^-1(x), where g^-1 is the inverse of g. Also state the domain and range of g^-1 in interval notation. g^-1(x) = Domain of g^-1 : Range of g^-1 :