Question

The one-to-one functions $g$ and $h$ are defined as follows. $g = \{(-8, 2), (-7, 8), (2, 4), (4, 5), (7, 1)\}$ $h(x) = \frac{-x + 13}{11}$ Find the following. $g^{-1}(4) = ?$ $h^{-1}(x) = ?$ $(h^{-1} \circ h)(2) = ?$

          The one-to-one functions $g$ and $h$ are defined as follows.
$g = \{(-8, 2), (-7, 8), (2, 4), (4, 5), (7, 1)\}$
$h(x) = \frac{-x + 13}{11}$
Find the following.
$g^{-1}(4) = ?$
$h^{-1}(x) = ?$
$(h^{-1} \circ h)(2) = ?$

$The one-to-one functions g and h are defined as follows. g = {(-8, 2), (-7, 8), (2, 4), (4, 5), (7, 1)} h(x) = (-x + 13)/(11) Find the following. g^-1(4) = ? h^-1(x) = ? (h^-1∘ h)(2) = ?$

Added by Robert C.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert James Kiss

06/16/2023

Step 1

Looking at the definition of g, we see that g(2) = 4. Therefore, g^{-1}(4) = 2. Show more…

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The one-to-one functions g and h are defined as follows. g={(-8, 2), (-7, 8), (2, 4), (4, 5), (7, 1)} h(x) = \frac{-x+13}{11} Find the following. g^{-1}(4) = h^{-1}(x) = (h^{-1} \circ h)(2) =