Question

The original 24 m edge length x of a cube decreases at the rate of 4 m/min. a. When x = 5 m, at what rate does the cube's surface area change? b. When x = 5 m, at what rate does the cube's volume change? a. When x = 5 m, the surface area is changing at a rate of - 240 m²/min. b. When x = 5 m, the volume is changing at a rate of m³/min.

          The original 24 m edge length x of a cube decreases at the rate of 4 m/min.
a. When x = 5 m, at what rate does the cube's surface area change?
b. When x = 5 m, at what rate does the cube's volume change?
a. When x = 5 m, the surface area is changing at a rate of - 240 m²/min.
b. When x = 5 m, the volume is changing at a rate of m³/min.

The original 24 m edge length x of a cube decreases at the rate of 4 m/min.
a. When x = 5 m, at what rate does the cube's surface area change?
b. When x = 5 m, at what rate does the cube's volume change?
a. When x = 5 m, the surface area is changing at a rate of - 240 m²/min.
b. When x = 5 m, the volume is changing at a rate of m³/min.

Added by Adam B.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Madhur L

04/12/2023

Step 1

We know that the edge length x of the cube is decreasing at a rate of 4 m/min. So, dx/dt = -4 m/min. Show more…

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The original 24 m edge length x of a cube decreases at the rate of 4 m/min. a. When x = 5 m, at what rate does the cube's surface area change? b. When x = 5 m, at what rate does the cube's volume change? a. When x = 5 m, the surface area is changing at a rate of - 240 m2/min. b. When x = 5 m, the volume is changing at a rate of m3/min.