00:01
So questions a and b for this whole question are essentially unit analysis.
00:08
So what we're going to do is we'll start with question a and we're looking to find the unit of a, which is going to be, well, how are we going to do that? when you look at into the unit analysis, you can look at any other terms first, if there are any that are being added to the term that contains what we're looking at.
00:30
So in this case, we have a here.
00:32
And this whole term, a n squared over v squared, is being added to p.
00:37
So i'll tell you in a second what the point of that is.
00:40
Why we care about that? first all, i just copied that part down.
00:45
And the point is, if they're going to be added, they need to have the same units.
00:50
So the unit of a n squared over v squared is going to be the same as the unit of p.
00:55
So essentially, the way we do unit analysis, not that it makes direct sense.
01:01
When you read these equations, but we just replace each value with its unit.
01:08
So what i'm going to do here is say that a n squared, not that it's equal, but it has the same, it has the unit of pressure, which is going to be, well, that's going to depend on what rate, what value are we're actually using, the gas constant.
01:31
So what i'm going to mention is that we're going to assume that r is equal to 0 .082 liters times atmosphere over kelvin times mole.
01:52
And this is just, you know, you're going to get a different answer if you use a different rate constant, such as 8 .314 in a different unit.
02:02
But the point is, and that's because it will have different units.
02:05
I chose this one, though, because the question c &d have the unit of atmosphere, and they give units similar to these, or involving these.
02:17
So we're going to assume that we're using this gas constant.
02:21
And in that case, from looking at this unit, which unit do you think is for pressure? it's going to be atmosphere.
02:30
So basically it's going to be atmosphere.
02:35
And then what are the units of n and v? well, n is moles.
02:43
So we're going to have mole squared, and v is going to be, look at the rate constant, and we have l liters.
02:57
And finally, to isolate a and to get our unit, we find that a is in the unit of, atmosphere times liter squared over mole square.
03:14
Now we're gonna do question b, a very similar way, which is, once again, we get, if the term involving what we're looking at, so b, and we have minus nb, that's being, well, we're subtracting nb from v, so basically i'm gonna write that down, just like before, we have v minus nb, and the point is to subtract, you're subtracting something, just like with adding, since adding is just adding a negative, they have to have the same unit.
03:46
So basically what we find is that nb, again, it's not actually equal, but rather it's in the unit, it'd be in the unit of volume, which from our gas constant is liters.
03:59
And then you get finally that b is in liters per mole.
04:13
And that is our answer for part b.
04:17
And now we can move on to see.
04:20
We're just going to, well, let me first write out the equation.
04:25
So yeah, now we have our equation.
04:28
And before we, it's up to you how you want to do this.
04:32
But before we sub things in, we can just isolate for what we're looking for, which is going to be.
04:41
Actually, we don't have, it's up to you whether you want to isolate.
04:46
P before submitting in or not.
04:48
But the way i'll do actually is rather, is not that, but i will, sorry, there is a mistake here, which is, that this, it's a b, it's just b times n.
05:01
But anyway, what we're going to do is, um, start, uh, subbing things in and we get, um, first of all, okay, p is the unknown.
05:10
So we just keep that as p.
05:12
But then, uh, we have a, which is, um, going to be 5 .464.
05:19
And then we're going to have, um, and then we're going to have, um, and over.
05:21
Over v like h squared.
05:24
That's the same as just n over v and then that entire thing squared...