Question

The peak of Genovia's epic rainstorm of 2017 occurred between 4 pm, Oct 11, and 4 am, Oct 12. During those 12 hours the rate of rainfall can be modeled by $r(t) = \frac{280e^{\frac{x}{3}}}{(60 + e^{\frac{x}{3}})^2}$ in inches per hour, where $t = 0$ represents 4 pm on Oct 11. Let $R(x) = \int_0^x \frac{280e^{\frac{x}{3}}}{(60 + e^{\frac{x}{3}})^2} dt$ Calculate R(4). Round to 2 decimal places if needed. What does R(4) represent in the context? R(4) = _____, which represents $\circ$ R(4) represents the accumulated rainfall from 4 pm to 8 pm on Oct 11 $\circ$ R(4) represents the rainfall at 4 pm on Oct 11 $\circ$ R(4) represents the rainfall at 8 pm on Oct 11

          The peak of Genovia's epic rainstorm of 2017 occurred between 4 pm, Oct 11, and 4 am, Oct 12. During those 12 hours the rate of rainfall can be modeled by $r(t) = \frac{280e^{\frac{x}{3}}}{(60 + e^{\frac{x}{3}})^2}$ in inches per hour, where $t = 0$ represents 4 pm on Oct 11.

Let $R(x) = \int_0^x \frac{280e^{\frac{x}{3}}}{(60 + e^{\frac{x}{3}})^2} dt$

Calculate R(4). Round to 2 decimal places if needed. What does R(4) represent in the context?
R(4) = _____, which represents
$\circ$ R(4) represents the accumulated rainfall from 4 pm to 8 pm on Oct 11
$\circ$ R(4) represents the rainfall at 4 pm on Oct 11
$\circ$ R(4) represents the rainfall at 8 pm on Oct 11

The peak of Genovia's epic rainstorm of 2017 occurred between 4 pm, Oct 11, and 4 am, Oct 12. During those 12 hours the rate of rainfall can be modeled by r(t) = (280e^(x)/(3))/((60 + e^(x)/(3))^2) in inches per hour, where t = 0 represents 4 pm on Oct 11.

Let R(x) = ∫0^x (280e^(x)/(3))/((60 + e^(x)/(3))^2) dt

Calculate R(4). Round to 2 decimal places if needed. What does R(4) represent in the context?
R(4) = , which represents
∘ R(4) represents the accumulated rainfall from 4 pm to 8 pm on Oct 11
∘ R(4) represents the rainfall at 4 pm on Oct 11
∘ R(4) represents the rainfall at 8 pm on Oct 11

Added by Sonya R.

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