Given:
$m_1 = 3$ kg, $y_1 = 0$ m (since the center of mass of the slender rod is at the end),
$m_2 = 5$ kg, $y_2 = 0$ m (since the center of mass of the thin plate is at the center).
Substitute the values into the formula:
$\bar{y} = \frac{3(0) + 5(0)}{3 + 5} =
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