The plane of a rectangular wire loop, 5.0 cm x 8.0 cm, is parallel to a magnetic field of 0.19 T. The loop carries a current of 6.2 A. (a) What is the magnetic torque acting on the loop? (b) What is the magnetic dipole moment of the loop?
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Step 1
Given: Current, I = 6.2 A Area of the loop, A = 0.05 m x 0.08 m = 0.004 m^2 Magnetic field strength, B = 0.19 T The formula for magnetic torque is τ = I * A * B Substitute the values: τ = 6.2 A * 0.004 m^2 * 0.19 T τ = 0.0047 Nm Show more…
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The plane of a 5.0 cm x 8.0 cm rectangular loop of wire is parallel to a 0.19-T magnetic field. The loop carries a current of 6.2 A. a. What torque acts on the loop?b. What is the magnetic moment of the loop?c. What is the maximum torque that can be obtained with the same total length of wire carrying the same current in this magnetic field?
Timothy J.
The plane of a 5.0 cm $\times$ 8.0 cm rectangular loop of wire is parallel to a 0.19-T magnetic field. The loop carries a current of 6.2 A. (a) What torque acts on the loop? (b) What is the magnetic moment of the loop? (c) What is the maximum torque that can be obtained with the same total length of wire carrying the same current in this magnetic field?
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A circular loop of wire of area $10 \mathrm{cm}^{2}$ carries a current of 25 A. At a particular instant, the loop lies in the $x y$ -plane and is subjected to a magnetic field $$\overrightarrow{\mathbf{B}}=(2.0 \hat{\mathbf{i}}+6.0 \hat{\mathbf{j}}+8.0 \hat{\mathbf{k}}) \times 10^{-3} \mathrm{T} . \quad \text { As } \quad \text { viewed }$$ from above the $x y$ -plane, the current is circulating clockwise. (a) What is the magnetic dipole moment of the current loop? (b) At this instant, what is the magnetic torque on the loop?
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