Question

The planes $4x + 2y + 4z = 10$ and $2x + 4y + 4z = -4$ are not parallel, so they must intersect along a line that is common to both of them. The vector parametric equation for this line is $L(t) = $

          The planes $4x + 2y + 4z = 10$ and $2x + 4y + 4z = -4$ are not parallel, so they must intersect along a line that is common to both of them. The vector parametric equation for this line is
$L(t) = $

Added by Andrea H.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Adi S

09/03/2023

Step 1

To find the direction vector of the line of intersection, we need to find the normal vectors of both planes. The normal vector of a plane is the coefficients of x, y, and z in the equation of the plane. For the first plane, 4x + 2y + 4z = 10, the normal vector is Show more…

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The planes 4x+2y+4z=10 and 2x+4y+4x=-4 are not parallel, so they must intersect along a line that is commin to both of them. The vector parametric equation for this line is The planes4z+2y+4z10 and2z+4y+4z=4 are not parallel,so they.must intersect along a fine that is common to both of them.The vector parametric equation for this line is Preview My Answers Submit Answers