The polynomial 6x³ + mx² + nx - 5 has a factor of x + 1. When divided by x - 1, the remainder is -4. What are the values of m and n?
Added by James A.
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We can do this by expanding the right side of the equation: (x+1)(Ax^2 + Bx + C) = Ax^3 + (B+A)x^2 + (C+B)x + C Now, we can compare the coefficients of the corresponding terms on both sides of the equation: 6x^3 = Ax^3 => A = 6 mx^2 = (B+A)x^2 => m = B+A => m = Show more…
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