Question

The position function of a simple harmonic oscillator (SHM) is given by X(t) = 6.0 m cos [(3? rad/s)t + ?/3 rad. What is the (a) period T of the oscillatory motion and (b) acceleration of the oscillation at t = 2 s (a) (b) A. 1.5s 1.3 x 10$^2$ m/s$^2$ B. 0.67s -2.7 x 10$^2$ m/s$^2$ C. 2.7s -3.9x 10$^2$ m/s D. 0.67 s -49 m/s$^2$ E. 1.5 s 0.65 x 10$^2$ m/s F. 2.7 s 4.9x 10$^2$ m/s

          The position function of a simple harmonic oscillator (SHM) is given by X(t) = 6.0 m cos [(3? rad/s)t + ?/3 rad. What is the (a) period T of the oscillatory motion and (b) acceleration of the oscillation at t = 2 s
(a)
(b)
A.
1.5s
1.3 x 10$^2$ m/s$^2$
B.
0.67s
-2.7 x 10$^2$ m/s$^2$
C.
2.7s
-3.9x 10$^2$ m/s
D.
0.67 s
-49 m/s$^2$
E.
1.5 s
0.65 x 10$^2$ m/s
F.
2.7 s
4.9x 10$^2$ m/s

The position function of a simple harmonic oscillator (SHM) is given by X(t) = 6.0 m cos [(3? rad/s)t + ?/3 rad. What is the (a) period T of the oscillatory motion and (b) acceleration of the oscillation at t = 2 s
(a)
(b)
A.
1.5s
1.3 x 10^2 m/s^2
B.
0.67s
-2.7 x 10^2 m/s^2
C.
2.7s
-3.9x 10^2 m/s
D.
0.67 s
-49 m/s^2
E.
1.5 s
0.65 x 10^2 m/s
F.
2.7 s
4.9x 10^2 m/s

Added by Jacqueline V.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Narayan Hari

05/28/2021

Step 1

Om cos[3TT rad/s)t+ T/3 rad X(t)=6.Om cos[3TT*rad/s]+T/3 rad X(t)=6.Om*cos[3TT*rad/s]+T/3 rad X(t)=6.Om*cos[9TT*rad/s]+T/9 rad X(t)=36.Om*cos[36TT*rad/s]+T/216 rad T=2s Show more…

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The position function of a simple harmonic oscillator (SHM) is given by X(t) = 6Ï‰ cos[3Ï€ rad/s(t) + Ï€/3 rad]. What is the period (T) of the oscillatory motion and the acceleration of the oscillation at t = 2s? (a) (b) A. 1.5s 1.3x10^2 m/s^2 B. 0.67s -2.7x10^2 m/s^2 C. 2.7s -3.9x10^2 m/s^2 D. 0.67s -49 m/s^2 E. 1.5s 0.65x10^2 m/s^2 F. 2.7s 4.9x10^2 m/s^2