The position of an object moving on a line is given by s(t) = 6t2-t3, t > 0, where s is in the metres and t is in seconds a. Determine the velocity and acceleration of the object at t = 2.
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Step 1
The position function is given by s(t) = 6t^2 - t^3. The derivative of s(t) with respect to t is: v(t) = ds/dt = d(6t^2 - t^3)/dt = 12t - 3t^2 Show more…
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