Question

3. The probability that a certain NBA basketball player makes a free throw shot is about 65% of the time. Find the probability that (a) (2 points) the first shot he makes is the second shot. (b) (2 points) the first shot he makes is the third or fourth shot. (c) (2 points) he does not make any of the first four shots he attemps.

          3. The probability that a certain NBA basketball player makes a free throw shot is about 65% of the time. Find the probability that
(a) (2 points) the first shot he makes is the second shot.
(b) (2 points) the first shot he makes is the third or fourth shot.
(c) (2 points) he does not make any of the first four shots he attemps.

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3. The probability that a certain NBA basketball player makes a free throw shot is about 65% of the time. Find the probability that
(a) (2 points) the first shot he makes is the second shot.
(b) (2 points) the first shot he makes is the third or fourth shot.
(c) (2 points) he does not make any of the first four shots he attemps.

Added by Jesse C.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

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Solved by Expert Maitreya E

05/12/2022

Step 1

The probability that the first shot he makes is a free throw and the second shot is also a free throw: Since the probability of making a shot is 65%, the probability of making two shots in a row is (0.65) * (0.65) = 0.4225 or 42.25%. Show more…

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The probability that a certain NBA basketball player makes about 65% of the time. Find the probability that: 1. The first shot he makes is a free throw and the second shot is also a free throw. 2. The first shot he makes is either the third or fourth shot. 3. He does not make any of the first four shots he attempts.

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Transcript

00:01 Hi everyone, welcome to the question.

00:04 So it is given p is equal to 65 percentage.

00:07 We have to find the probability that the first shot he makes is the second shot.

00:12 So let's first solve subdivision a.

00:15 So p is equal to 65 percentage we converted into 0 .65.

00:20 So 1 minus p is equal to 1 minus 0 .65.

00:25 That is equal to 0 .35.

00:27 So probability that he doesn't make a free shot.

00:31 Is 0 .35.

00:33 So now p of x is equal to 2 probably that he makes the first shot in the second shot.

00:42 So that is x is equal to 2.

00:43 So that is equal to 0 .65 multiplied by 0 .35.

00:50 So that is equal to when you multiply it is 0 .275.

00:55 So from this you can write probability that the first shot he makes is the second shot 0 .2 to 75 so this is the answer for the a subdivision moving on to the b part when the b sub part they have given us the first shot he makes is the second or the fourth shot so here it is p of x is equal to three or p of x or p of x is equal to 4.

01:47 So we can write this as p of x is equal to 3 plus p of x is equal to 4.

01:54 So that is equal to so on the third shot he makes his free shot.

01:59 So 0 .35 multiplied by 0 .35 multiplied by 0 .65 plus on his fourth shot he makes three shot so a 0 .35 multiplied by 0 .65 multiplied by 0 .35 multiplied by 0 .65, multiplied by 0 .65.

02:23 So that is equal to 0 .0796 plus 0 .078...

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