00:01
In this problem, we are given the following joint density probability function.
00:07
F of x, y equal to c times x times 1 plus y when x is between 0 and 2 and y is between 0 and 6 and it is 0 otherwise.
00:24
Okay, we have three parts so let's get started with the first one.
00:29
In the first part, we will compute, we will find the value of this constant c and we will obtain it using the normalization condition.
00:39
So if we integrate our function over the entire space, we should get 1.
00:47
So restricting ourselves to the region where our function is non -zero, we have integral from 0 to 2 dx, integral from 0 to 6 dy, c times x times 1 plus y equal to 1.
01:04
Okay, these will be all elementary integrals so let me just write down the result.
01:08
For the y integral, we have 24 x times c and for the x integral, we have 48 c.
01:19
Therefore, we see that c should be equal to 1 over 48.
01:28
In the next part, we will compute the probability that x is less than or equal to 1 and y is less than or equal to 1.
01:40
Okay, we have integral from minus infinity to 1 dx, integral from minus infinity to 1 dy, f of x y.
01:51
And again, considering only the region where our function is non -zero, we have integral from 0 to 1 dx, integral from 0 to 1 dy, c times x times 1 plus y.
02:07
Okay, again i will just write down the results for these integrals...