The rate of change of the unit price $p$ (in dollars) of Apex women's boots is given by $$ p^{\prime}(x)=\frac{-250 x}{\left(16+x^{2}\right)^{3 / 2}} $$ where $x$ is the quantity demanded daily in units of a hundred. Find the demand function for these boots if the quantity demanded daily is 300 pairs $(x=3)$ when the unit price is $\$ 50 /$ pair.
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$$ p(x) = \int p'(x) dx = \int \frac{-250 x}{\left(16+x^{2}\right)^{3 / 2}} dx $$ This is a standard form of integral that can be solved by substitution. Let $u = 16 + x^2$, then $du = 2x dx$. The integral becomes: $$ p(x) = -125 \int \frac{du}{u^{3/2}} = -125 Show moreā¦
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The rate of change of the unit price $p$ (in dollars) of Apex women's boots is given by $$p^{\prime}(x)=\frac{-250 x}{\left(16+x^{2}\right)^{3 / 2}}$$,where $x$ is the quantity demanded daily in units of a hundred. Find the demand function for these boots if the quantity demanded daily is 300 pairs $(x=3)$ when the unit price is $\$ 50 /$ pair.
Integration
Integration by Substitution
Refer to Section $6.7 .$ The demand function for Apex women's boots is $$p=\frac{250}{\sqrt{16+x^{2}}}$$ where $p$ is the unit price in dollars and $x$ is the quantity demanded daily, in units of a hundred. Find the consumers' surplus if the price is set at 50 dollar pair.
Additional Topics in Integration
Integration Using Tables of Integral
Demand Suppose a demand function is given by $$ q=D(p)=30\left(5-\frac{p}{\sqrt{p^{2}+1}}\right) $$ where $q$ is the demand for a product and $p$ is the price per item in dollars. Find the rate of change in the demand for the product per unit change in price (i.e., find $d q / d p )$ .
Calculating the Derivative
The Chain Rule
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