00:01
Okay, so what we're looking at is d, y, d, d, t, because it's the rate of change of y with respect to t, is, so equals three times the value of the quantity.
00:13
So, parentheses, this is kind of confusing, when they say two less than y, you've got to do y minus two.
00:18
So what i would do in this problem is i would separate my variables.
00:23
So i could divide, see, that's multiplication, so i'm dividing y minus two to the left side, and i can multiply.
00:30
By d t to the right side.
00:32
So at this point, we can integrate on both sides.
00:36
And on the left side, when it's in the denominator, it's going to be the natural log of the absolute value of y minus 2.
00:44
Now, on the right side, the integral of that would be 3t plus c.
00:48
Now, what i would do is solve for natural log on this.
00:54
And all i'm doing is take an e to both sides, so e to the 3t plus c.
00:58
But a lot of times what we'll do is we'll rewrite that.
01:01
I'm going to use k for c...