The relative fitness values of three genotypes are: wAA = 1.0, wAa = 1.0, and waa = 0.7. What is the predicted equilibrium allele frequency if the rate of mutation of A to a is 2 x 10^-5? a. q hat = 0.022 and p hat = 0.978 b. q hat = 0.008 and p hat = 0.992 c. q hat = 0.005 and p hat = 0.995 d. q hat = 0.011 and p hat = 0.989
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0045 p = 1 - q ≈ 1 - 0.0045 = 0.9955 Show more…
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The relative fitness values of three genotypes are wA/A = 1.0, wA/a = 1.0, and wa/a = 0.7. a. If the population starts at the allele frequency p = 0.5, what is the value of p in the next generation? b. What is the predicted equilibrium allele frequency if the rate of mutation of A to a is 2 × 10^(-5)?
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Consider 10 populations that have the genotype frequencies shown in the following table: a. Which of the populations are in Hardy-Weinberg equilibrium? b. What are $p$ and $q$ in each population? c. In population $10,$ the $A \rightarrow a$ mutation rate is discovered to be $5 \times 10^{-6}$. What must be the fitness of the $a / a$ phenotype if the population is at equilibrium? d. In population $6,$ the $a$ allele is deleterious; furthermore, the $A$ allele is incompletely dominant; so $A / A$ is perfectly fit, $A / a$ has a fitness of $0.8,$ and a/a has a fitness of $0.6 .$ If there is no mutation, what will $p$ and $q$ be in the next generation?
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