The rotational constant of ^1^2C^1^6O_2 is 0.39021 cm^-^1. Calculate the bond length of the molecule if ^1^2C = 12 amu exactly and ^1^6O = 15.99949 amu. Assuming the same bond length, what would be the rotational constant of ^1^2C^1^6O^1^5O? What type of effect is this?
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First, we need to find the reduced mass (µ) of the 12C16O2 molecule. The reduced mass is given by the formula: µ = (m1 * m2) / (m1 + m2) where m1 and m2 are the masses of the two atoms in the molecule. In this case, m1 = 12 amu and m2 = 15.99949 amu. Show more…
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