Question

The sequence below is the coding strand of the first 20 codons of the human Beta globin gene. 5’- ATG GTG CAT CTG ACT CCT GAG GAG AAG TCT GCC GTT ACT GCC CTG TGG GGC AAG GTG AAC -3’ What is the sequence of the template strand for this region? 5' - GTT CAC CTT GCC CCA CAG GGC AGT AAC GGC AGA CTT CTC CTC AGG AGT CAG ATG CAC CAT - 3' 3' - GTT CAC CTT GCC CCA CAG GGC AGT AAC GGC AGA CTT CTC CTC AGG AGT CAG ATG CAC CAT - 5' 5'- GUU CAC CUU GCC CCA CAG GGC AGU AAC GGC AGA CUU CUC CUC AGG AGU CAG AUG CAC CAU- 3' 5'- ATG GTG CAT CTG ACT CCT GAG GAG AAG TCT GCC GTT ACT GCC CTG TGG GGC AAG GTG AAC - 3

          The sequence below is the coding strand of the first 20 codons of the human Beta globin gene.
5’- ATG GTG CAT CTG ACT CCT GAG GAG AAG TCT GCC GTT ACT GCC CTG TGG GGC AAG GTG AAC -3’
What is the sequence of the template strand for this region?
5' - GTT CAC CTT GCC CCA CAG GGC AGT AAC GGC AGA CTT CTC CTC AGG AGT CAG ATG CAC CAT - 3'
3' - GTT CAC CTT GCC CCA CAG GGC AGT AAC GGC AGA CTT CTC CTC AGG AGT CAG ATG CAC CAT - 5'
5'- GUU CAC CUU GCC CCA CAG GGC AGU AAC GGC AGA CUU CUC CUC AGG AGU CAG AUG CAC CAU- 3'
5'- ATG GTG CAT CTG ACT CCT GAG GAG AAG TCT GCC GTT ACT GCC CTG TGG GGC AAG GTG AAC - 3

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Added by Silvia M.

Biology for AP Courses

Julianne Zedalis, John Eggebrecht

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Solved by Expert Joanna Quigley

02/26/2022

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Step 1: Identify the coding sequence given: 5'- ATG GTG CAT CTG ACT CCT GAG GAG AAG TCT GCC GTT ACT GCC CTG TGG GGC AAG GTG AAC -3' Show more…

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The sequence below is the coding strand of the first 20 codons of the human Beta globin gene. 5’- ATG GTG CAT CTG ACT CCT GAG GAG AAG TCT GCC GTT ACT GCC CTG TGG GGC AAG GTG AAC -3’ What is the sequence of the template strand for this region? 5' - GTT CAC CTT GCC CCA CAG GGC AGT AAC GGC AGA CTT CTC CTC AGG AGT CAG ATG CAC CAT - 3' 3' - GTT CAC CTT GCC CCA CAG GGC AGT AAC GGC AGA CTT CTC CTC AGG AGT CAG ATG CAC CAT - 5' 5'- GUU CAC CUU GCC CCA CAG GGC AGU AAC GGC AGA CUU CUC CUC AGG AGU CAG AUG CAC CAU- 3' 5'- ATG GTG CAT CTG ACT CCT GAG GAG AAG TCT GCC GTT ACT GCC CTG TGG GGC AAG GTG AAC - 3

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Transcript

00:01 We've been given the coding strand for the first 20 codons of the beta -globin gene.

00:06 We want to know the template strand.

00:08 We've got four possible options here.

00:11 Okay, so there are two rules you need to know if you want to work out the complementary sequence to this strand.

00:18 First of all, you need to know, but there are pair -binding rules.

00:24 And i'll put urisyl in.

00:26 So adenine goes to thymine or uracil.

00:28 Satazine goes to guan.

00:31 So are we looking at thymine or urosil here? thymine is for dna.

00:36 Euracil is for rna.

00:39 And both the coding and template strand are made of dna.

00:42 They have the two strands of dna.

00:45 So coding and templates are the two dna strands.

00:52 What's the difference? well, template is one that the mrna is actually being transcribed from.

00:58 So the mrna is complementary to the template.

01:01 The coding is also complementary to the template because they're usually bound in the double -stranded dna structure.

01:09 So we're using this rule, we also need to know that nucleic acids bind anti -parallel to each other.

01:19 So what do i mean by this? well, if i draw the strands that we've been given, it starts at 5 -fram, it ends at 3 -prime...

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