Question

The series \sum_{n=1}^{\infty} \frac{3n^2 + 2n}{4 + n + n^2} a. converges by nth partial sum b. diverges by nth partial sum c. converges by nth term test d. diverges by nth term test

          The series \sum_{n=1}^{\infty} \frac{3n^2 + 2n}{4 + n + n^2}
a. converges by nth partial sum
b. diverges by nth partial sum
c. converges by nth term test
d. diverges by nth term test
        
The series ∑n=1^∞ (3n^2 + 2n)/(4 + n + n^2)
a. converges by nth partial sum
b. diverges by nth partial sum
c. converges by nth term test
d. diverges by nth term test

Added by Victor Manuel G.

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Calculus: Early Transcendentals
Calculus: Early Transcendentals
James Stewart 8th Edition
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The series sum_(n=1)^(infty ) (3n^(2)+2n)/(4+n+n^(2)) a. converges by nth partial sum b. diverges by nth partial sum c. converges by nth term test d. diverges by nth term test 3n2+ 2n The series n=1 4 + n + n2 O a. converges by nth partial sum O b. diverges by nth partial sum O c. converges by nth term test O d. diverges by nth term test
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Transcript

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00:01 In this question, we're going to determine the convergence or divergence of the series summed from n equals 1 to infinity of the arc tangent of 2n.
00:11 Now, if i look at my answer choices, i realize that we're interested in the nth term test and the integral test in this question.
00:21 Now, the nth term test is a test for divergence only.
00:28 So therefore, answer choice a makes no sense.
00:33 Nothing can ever converge by the nth term test.
00:38 So let's run through the nth term test.
00:41 The nth term test says i should look at the limit as n approaches infinity of my general term.
00:49 In this case, the limit as n approaches infinity of the arc tangent of 2n.
00:56 To evaluate this limit, we imagine plugging in as n approaches infinity, 2n approaches infinity as well.
01:07 So we are taking the arc tangent of something approaching infinity.
01:12 When you take the arc tangent of something very, very large, the result gets very close to pi over 2.
01:22 This result gets very, very close to pi over 2.
01:26 Now, what's important about that? for our purposes, it's important that that's not 0...
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