The side of a cube increases at a rate of 1/3 m/s Find the rate (in m3/s) at which the volume of the cube increases when the side of the cube is 5 m. m/s.
Added by Kevin O.
Step 1
We are given that the side of the cube increases at a rate of $\frac{1}{3}$ m/s. Let's denote the side length of the cube as $s$ and its rate of change as $\frac{ds}{dt}$. So, we have: $$\frac{ds}{dt} = \frac{1}{3}$$ Show more…
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