00:01
We have three calculations to do with silver, and we are told that the specific heat of silver is equal to 0 .24 j over g degrees c.
00:25
For question a, we're asking to find the heat energy, which i will hereafter refer to as q, to raise the temp of mass of 150 .0 grams of silver.
00:54
And i've got a final temperature and an initial temperature given as 298k and 273k which means my change in temperature will be equal to 25k and a note 25k equals 25 degrees c we will be using q equals mc delta t to solve for q.
01:37
There's all my givens for this question, so q will equal mass times specific heat, and i'm just going to go gk here, times 25k.
02:00
I can report this to, because of my temperature only, i guess i could do three significant figures.
02:08
Nope, i can only do two significant figures.
02:11
150 times 0 .24 times 25.
02:16
This is 900, 150 times 24 times .25.
02:25
So i'm going to go 9 .0 times 10 to the second joules.
02:40
And that's good...