The sublimation of dry ice solid co2 to give gaseous co2 is...

The sublimation of dry ice, solid CO2, to give gaseous CO2, is spontaneous at room temperature. This process: A. is spontaneous at all temperatures because ΔH is negative and ΔS is positive. B. is spontaneous at high temperatures because ΔH and ΔS are both positive. C. is spontaneous at high temperatures because ΔH and ΔS are both negative. D. is spontaneous at low temperatures because ΔH and ΔS are both negative. E. is spontaneous at low temperatures because ΔH and ΔS are both positive. Which one of the following statements is true about the equilibrium constant for a reaction if ΔG° for the reaction is negative? A. Keq = 0 B. Keq = 1 C. Keq > 1 D. Keq < 1 E. More information is needed. In the balanced equation, the reducing agent is ________. 3H2S(aq) + H+ (aq) + NO3- (aq) → 3S(s) + 2NO(g) + 4H2O(l) A. H2S B. H+ C. NO3- D. 3S(s) E. H2O(l)

Transcript

00:01 Hello students welcome here in this question we have a reaction that is given here soil co2 is converting to gas gase co2 so here solid co2 is sublimation this reaction is so sublimation means the compound is converting from solid to gas so this reaction is given as spontaneous reaction.

00:40 Spontaneous reaction means it doesn't require any energy.

00:46 So it occurs on self.

00:51 So there is no need of any activation.

00:55 So this is spontaneous energy.

00:57 So here delta s for this reaction is positive.

01:02 We know that because it is confirmed here with very less delta s is present here it is very high delta s is present so i guess is delta s is positive here and we know that delta g for this reaction is negative so delta g should be negative then it is minus delta h plus t ds is the formula so what is here the condition is this should be negative it is it should be negative means this should be positive.

01:41 Delta h should be positive and we know that delta s is a positive.

01:47 So delta s is positive and this one is also positive.

01:51 So what we should have this one should be high.

01:55 That's why this value should be less than temperature should be very less.

02:00 So temperature should be low temperatures are possible when delta g is positive.

02:07 Negative.

02:09 So then only the reaction is spontaneous.

02:16 So t is low and delta h is positive and delta s is positive then only the reaction will be spontaneous.

02:26 So here in this question option e is correct answer which is given as at low temperature.

02:35 So this reaction is spontaneous at low temperature.

02:36 So this reaction is spontaneous at low.

02:43 Temperatures and both delta h and delta s are positive okay and the next option here next question is given here so the question is the second question if delta g is negative then which one is a correct statement for k value so we know that delta g not is equal to so here you it is g0 is equal to minus r t l nk.

03:21 So if k value is less than 1, then it is equal to 0.

03:31 So this is greater, so positive value.

03:36 G0 should be, g0 will be positive if it is k less than 1.

03:41 If k is equal to 1, it should be 0.

03:44 So delta g0 is equal to 0.

03:47 And the value k is equal to 1 means it is 0.

03:52 All total value will become 0...