The sum of the first n odd squares is 4/3(n)^3 - 1/3(n). Solve by induction.
Added by Catalina R.
Step 1
When n = 1, the sum of the first odd square is 1^2 = 1. Substitute n = 1 into the given formula: 4/3(1)^3 - 1/3(1) = 4/3 - 1/3 = 1. Therefore, the base case holds true. Show more…
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