00:01
Now here in this question, basically, we are looking at the average number of daylight hours, right? in particular, six months, and with x indicates months, right? so these are the data, right? and you ask, you know, you're giving that the, this daylight hours, you know, are given by this function, right? you're asked to find the, basically, the parameter in this function, right? it's a simple sign function, shifted a little bit, right? offset a little bit by d, right? so you can, we can actually first find the period, i mean, the period b, i mean, the period, is given by 2 pi over a b, right? and that's given by, you look at the period of course from january to november, right? i think that would give you from january to november.
00:44
If that's a period, yeah, that seems to be the period, right? i think that's period from january to november, right? so that's a period.
00:52
Of course, is november 11 minus january 1, so it's 10, right? so that's 10 months.
00:58
So we find actually b is given by 2 % over 10.
01:01
So it's actually pi over five, right? and so that is the b, right? the value of b we found is pi over five, right? and of course, in a similar way, we can find, for example, we can find the amateur.
01:17
This is just constant.
01:18
So basically the a, you know, if you double a, there must be the highest point, the difference between high spawn, low spawn.
01:25
So the lowest point seems to be four, right? what is the high spawn? well, the high spawn tends to be, i think, 19 .6, right? so that's 19 .6 minus 4...