the table that should not be used. $x \to 2^+$ $\frac{x^3 - 8}{3^x - 9}$ 2.1 2.01 2.001 2.0001 2.00001 2.000001 From the numerical estimation table, we conclude that $\lim_{x \to 2^+} \frac{x^3 - 8}{3^x - 9} = $
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Substituting x = 2 gives (8 - 8)/(9 - 9) = 0/0, an indeterminate form. Show more…
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