The uniform beam has a mass of 54 kg per meter of length....

Transcript

00:01 In this question, there is a beam.

00:03 This is the beam.

00:06 At this end, this is the roller support, a.

00:11 And at b point, there is a pin support.

00:13 This is point b.

00:15 There is a crate.

00:18 The mass of the crate is 210 gage.

00:22 And this is 1 .1 meter distance from support b.

00:27 And from support a, this is 2 .2 meter.

00:30 So you can see the length of the base.

00:32 Beam is 2 .2 plus 1 .1 you will get 3 .3 meter is the length of the beam now the beam has mass the mass of the beam is given as the mass of the beam is 54 kg per meter so mass of the beam is 54 times 3 .3 so mass is 54 and length of the beam is 3 .3.

01:05 So you will get the mass of the beam is 178 .2 kg.

01:12 This is the mass of the beam.

01:14 So let's draw the free body diagram.

01:17 So this is the vertical direction.

01:20 In this direction, this is the horizontal force.

01:24 Bx.

01:24 We are calculating the reaction supports.

01:27 So this is a in vertical direction.

01:30 There is only one force.

01:31 Weight of the block.

01:33 This is mass times gravity so this is 200 210 times acceleration due to gravity so after multiplication 9 .8 1 you will get the weight 2060 .1 newton this is acting from 1 .1 meter distance now mass of the beam is already given so weight of the beam is acted at sector of the center of this beam so center of this beam is 1 .65 meter distance from a and from b...

Question

The uniform beam has a mass of 54 kg per meter of length. Determine the reactions at the supports. y 2.2 m 1.1 m 210 kg A B Answers: Ay = 7416.65 N Bx = 0 N By = N

Question

The uniform beam has a mass of 54 kg per meter of length. Determine the reactions at the supports. y 2.2 m 1.1 m 210 kg A B Answers: Ay = 7416.65 N Bx = 0 N By = N

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