Question

The vestigial gene (vg) in fruit flies can have a mutation, vg-, that confers tiny, useless wings; this phenotype is recessive to wild-type wings. The vestigial gene is on chromosome 2. The gene, hairy (h), in fruit flies can have a mutation, h-, that confers a hairy body; this phenotype is recessive to a wild-type, non-hairy body. The hairy gene is on chromosome 3. In fruit flies, the sex chromosome is chromosome 4. A vestigial-winged, hairy male is crossed with a wild-type female, homozygous at both genes. This F1 generation is crossed to produce the F2 generation. Which of the following are accurate regarding this F1 cross? There are 3 correct answers. The F1xF1 cross can be shown by a 4x4 Punnett square; the gamete genotypes along the top are vg+h+, vg+h-, vg-h+, vg-h-, and the gamete genotypes along the side are the same. There is no linkage between the hairy and vestigial genes. The F1xF1 cross can be shown by a 2x2 Punnett square; if the gamete genotypes along the top are vg+vg+ and h+h+, then the gamete genotypes along the side are vg-vg- and h-h-. The alleles of the vestigial gene and the alleles of the hairy gene will assort independently when the F1 generation makes gametes during meiosis. The maternal and paternal alleles of the hairy gene cannot segregate because the vestigial gene is on another chromosome.

          The vestigial gene (vg) in fruit flies can have a mutation, vg-, that confers tiny, useless wings; this phenotype is recessive to wild-type wings. The vestigial gene is on chromosome 2. The gene, hairy (h), in fruit flies can have a mutation, h-, that confers a hairy body; this phenotype is recessive to a wild-type, non-hairy body. The hairy gene is on chromosome 3. In fruit flies, the sex chromosome is chromosome 4. A vestigial-winged, hairy male is crossed with a wild-type female, homozygous at both genes. This F1 generation is crossed to produce the F2 generation. Which of the following are accurate regarding this F1 cross? There are 3 correct answers.

The F1xF1 cross can be shown by a 4x4 Punnett square; the gamete genotypes along the top are vg+h+, vg+h-, vg-h+, vg-h-, and the gamete genotypes along the side are the same.

There is no linkage between the hairy and vestigial genes.

The F1xF1 cross can be shown by a 2x2 Punnett square; if the gamete genotypes along the top are vg+vg+ and h+h+, then the gamete genotypes along the side are vg-vg- and h-h-.

The alleles of the vestigial gene and the alleles of the hairy gene will assort independently when the F1 generation makes gametes during meiosis.

The maternal and paternal alleles of the hairy gene cannot segregate because the vestigial gene is on another chromosome.

Added by Jasmine A.

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