Question

The waiting times for all customers at a supermarket are normally distributed with a mean of 5.5 minutes and a standard deviation of 1.5 minutes. Find the probability that the waiting time for a randomly selected customer at this supermarket will be more than 3.25 minutes.

          The waiting times for all customers at a supermarket are normally distributed with a mean of 5.5 minutes and a standard deviation of 1.5 minutes. Find the probability that the waiting time for a randomly selected customer at this supermarket will be more than 3.25 minutes.
        
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The waiting times for all customers at a supermarket are normally distributed with a mean of 5.5 minutes and a standard deviation of 1.5 minutes. Find the probability that the waiting time for a randomly selected customer at this supermarket will be more than 3.25 minutes.

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Elementary Statistics a Step by Step Approach
Elementary Statistics a Step by Step Approach
Allan G. Bluman 9th Edition
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The waiting times for all customers at a supermarket are normally distributed with a mean of 5.5 minutes and a standard deviation of 1.5 minutes. Find the probability that the waiting time for a randomly selected customer at this supermarket will be more than 3.25 minutes.
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Transcript

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00:02 Hi, let's do this question.
00:03 So here first let x be the waiting time for all customers, then x follows normal distribution with mean, mu equals to 5 .5 minutes, and standard deviation, sigma equals to 1 .5 minutes.
00:41 Is we have to determine the probability x greater than 3 .25 that is equal to probability of x minus mu over sigma greater than 3 .25 minus 5 .5 over 1 .5 so this is going to be equal to probability of z greater than minus 1 .5 so this is going to be equal to probability of z greater than minus 1 .5 so this is equal to 1 minus probability of z being less than equals to minus 1 .5.
01:21 So using z table we have the value 0 .0668...
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