Let's assume the time spent by customers in a supermarket is normally distributed with a mean of 45 minutes and a standard deviation of 15 minutes. What is the probability that the mean shopping time of 64 customers is less than 42 minutes?
Added by Jan D.
Step 1
The standard error of the mean is the standard deviation divided by the square root of the sample size. In this case, the standard deviation is 15 minutes and the sample size is 64 customers. So, the standard error of the mean is 15 / sqrt(64) = 15 / 8 = 1.875 Show more…
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