The weight of female cats of a certain breed are normally distributed with mean 4.2 kg in standard deviation of 0.6 kg. a) A certain female cat has a wait that is 0.5 standard deviation's above the mean. What proportion of female cats are heavier than this one?b) A female cat is chosen at random. What is the probability that she weighs more than 4.5 kg?c) Six female cats are chosen at random. What is the probability that none of them weigh more than 4.5 kg? (hint: weight of cats are independent of each other)
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5 standard deviations above the mean: \[ P(X > 4.5) = P(Z > \frac{4.5 - 4.2}{0.6}) = P(Z > 0.5) = 0.3085 \] ** Show more…
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