00:01
Hello students, according to the given question we have to find the probability values.
00:06
So, given mu is equal to 4 and sigma is equal to 0 .6, x follows normal distribution with mean mu and variance sigma square.
00:14
In the a bit we have to find probability of 3 .8 less than x less than 4 .4.
00:22
So, that can be written as probability of 3 .8 minus 4 divided by 0 .6 less than x minus mu is divided by sigma is less than 4 .4 minus 4 divided by 0 .6.
00:38
So, that is equal to probability of minus 0 .33 less than z less than 0 .6667.
00:45
So, from z table the value is 0 .37806.
00:51
Now, in the b bit they have given the weight is equal to 0 .7 into standard deviation that is equal to 0 .7 into 0 .6 that is equal to 0 .42.
01:04
So, we have to find probability of x greater than 0 .42 that is equal to probability of x minus mu by sigma is greater than 0 .42 minus minus 4 is divided by 0 .6...