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Precalculus with Limits
Precalculus with Limits
Ron Larson 2nd Edition
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Transcript

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00:01 For this question, they're giving us this quadratic, and it wants us to find everything about this quadratic.
00:07 So the first thing it wants us to find is if this parabola, this quadratic opens up or down.
00:12 And i know this is going to open up because my leading coefficient, the number in front of my x squared, is a positive number.
00:20 So i know it's going to be a quadratic that looks like this.
00:24 Then i wants us to find the coordinate of my vertex.
00:28 So to find my vertex, i'm going to use that.
00:31 Axis symmetry and then plug that in so i'm going to actually knock you know two birds with one stone by doing this so my axis symmetry is going to be negative b over 2a this is also going to be my x coordinate for my vertex so remember this is my a my b my c value so i'm going to plug it in negative b would be negative 4 over two times my a well my a there's a one here so it's going to be a 1, which gives me negative 2.
01:05 So my axis of symmetry is at x negative equals negative 2.
01:13 And now to find my vertex, i know that my vertex is going to be negative to something.
01:21 To find the y value, i'm just going to plug it back into my function.
01:25 I'm going to plug negative 2 into my x.
01:29 Now, i would be very careful here.
01:32 Everywhere you're plugging in, i would put a parentheses.
01:34 So negative 2 squared is positive 4.
01:38 4 times negative 2 is going to be negative 8 minus 12, is negative 4 minus 12, which is negative 16.
01:51 So my vertex is at negative 2, negative 16.
01:57 So now i found my, that it opens up, i found my axis of symmetry to be negative 2...
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