00:01
So you're given a strand of template dna of a gene.
00:06
So the question asks you to write down mrna sequence first, and then draw a label diagram with the first two codon of the material and a window, and also indicate the direction of the mrna and also use an arrow to indicate the direction of amino acid transfer that would occur.
00:24
So i use black color to represent the template dna strand.
00:29
So we know that during transcription, the template strand of dna is used as a template to produce new mrna.
00:36
The new mrna is complementary to the template string.
00:40
So this gives us two information.
00:42
First of all, the direction or orientation of the mra is the opposite to the dna.
00:48
So as you can see, i use red color to write down the mrn.
00:51
So we knew that it's complementary sequence.
00:54
So the five prime end of the mrn is the opposite to the dna, which is on the left side.
01:02
And the 3 prime end of mrna is on the right side.
01:05
So you can see the two strands are opposite orientation.
01:08
Now, it also followed the base pair rule when it comes to complementary strength.
01:14
Whenever there is a t in dna, and you're gonna pair up with an a in mra.
01:20
And whenever there's a a, now, since there's no t in mra, you have to replace that with a ura cell.
01:27
Now, c also pair with g.
01:29
So according to the base pair rule, i have written down the mrna c for you in red color already.
01:34
All right, so now the second part, you want to draw a diagram of translation where the m rna is being translated into polypeptide by ribosone.
01:43
So the line on the left side of the first code on the line on the right after the last code is called the utr region, untranslated region.
01:56
So 5 prime uti is where the ribosome binds, and it actually scans through the mrna to translate.
02:02
So the ribosome translates mrna in the format of codon.
02:07
A codon is every three nucleotide.
02:10
So aug is the first codon.
02:13
So a codon will give you a specific amino acid.
02:17
So this information can be found by the codon usage table that's given by the question.
02:22
Now the very first codon of the peptide is called the stark codon.
02:28
It is also a methionine.
02:29
So aug is the very first codon of the peptide.
02:32
Of this polypeptide.
02:34
So it gives you amino acid methionine.
02:37
So i'm using green color to write down the antichotone on t -r -n -a.
02:43
The anti -codone is, again, complementary to the codon on an m -r -n -a.
02:47
So as you can see, the first anticoad on t -r -n -a is from 5 to 3, c -a -u...