Question

Show that \(\mathbb{Q}(\sqrt{5} + \sqrt[4]{5})\) is Galois over \(\mathbb{Q}\) and determine the Galois group.

          Show that \(\mathbb{Q}(\sqrt{5} + \sqrt[4]{5})\) is Galois over \(\mathbb{Q}\) and determine the Galois group.
        
Show that ℚ(√(5) + √(5)) is Galois over ℚ and determine the Galois group.

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Calculus: Early Transcendentals
Calculus: Early Transcendentals
James Stewart 8th Edition
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This is my third time uploading this question. 1. do not do 5 + 5^(12) that is not the same as the square root of 5+5^(1/2). 2. please show the roots so that I can follow the solution clearly. Show that Q(/5 + /5) is Galois over Q and determine the Galois group
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Transcript

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00:01 Here in this question we have given a polynomial f x which goes to x to the power 4 plus x to the power u 3 plus x square plus x plus 1 is equal to 0 and we need to determine the goaliest group of this polynomial polynomial so first we'll do is what we'll do is we will take x square as common so it will be x square plus 1 plus 1 x square plus 1 plus 1 plus 1 is close to 0 from here x square plus 1 x square plus 1 plus 1 is equals to 0 .30902 plus 0 .902 plus 0 .95 .0 6 i 6 i which will be equals to alpha 1 x2 is equal to 0 .3902 minus 0 .95106 i which is equal to minus alpha 1 and x3 is equal to minus 0 .80902 plus 0 .5 i which will be equal to plus alpha 2 and the value of x4 is equals to minus 0 .8092 902 minus 0 .5879 i which will equal to minus alpha 2 so from here as given q alpha 1…
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