00:01
In this question we are asked to find the voltage across resistance are 3.
00:05
So let's start to solve this problem.
00:07
Here we are solving this problem by using kirchop voltage low.
00:10
To apply kirchof voltage low, let's assume that current flowing in this loop is equal to i1 and current flowing in this loop is equal to i2.
00:24
Now by applying kirchof voltage low in loop number 1 we obtain this following equation.
00:30
We are starting from this voltage source plus 5 because we are moving from negative terminal to positive terminal.
00:42
Negative 13, i1, negative 19, i1 plus 5 minus 17.
00:57
Current flowing through this resistor in the upper direction is equal to i1 minus i2 equals to 0.
01:07
Here and here we take negative sign because voltage drop takes place across the resistance...