Question

• This problem is a famous statistical problem. It is based on the TV Game Show: Let's Make a Deal with host, Monty Hall. • The problem is simple. You're on a game show and you're given the choice of three doors. Behind one door is a car; behind the other two doors are goats. You choose one door and the host (who knows what's behind the doors) opens another door which has a goat behind it. You are then allowed to stay with the door you picked, or switch to the other door. • Your objective is to decide on the best strategy for playing the game. Should you STAY with the door you originally chose? Should you SWITCH to the other unopened door? Or does it not make any difference in terms of your likelihood of winning the car? • The bonus on the test will ask a question about the probability of winning with the 2 different choices: STAY or SWITCH. • Two people: One person is Monty Hall and the other Person is the Contestant. • Take 3 cards of the same color. Write Car on one of the cards and write Goat on the other 2 cards. • Monty Hall shuffles the cards, looks at what is on each card and places the cards face down in front of the contestant. • The contestant selects a "door" of his/her choice. • Monty Hall turns over one of the other 2 cards that has a Goat. • Contestant now can choose to STAY with 1st choice or SWITCH to the other "door" that has not been opened. Your objective is to find P(winning) by STAYING and P(winning) by SWITCHING. Is there a better strategy or does it not make any difference? To answer, you need to play the game a large number of times and choose different strategies and then calculate the probability of winning with each strategy.

• This problem is a famous statistical problem. It is based on the TV Game Show: Let's Make a Deal with host, Monty Hall.
• The problem is simple. You're on a game show and you're given the choice of three doors. Behind one door is a car; behind the other two doors are goats. You choose one door and the host (who knows what's behind the doors) opens another door which has a goat behind it. You are then allowed to stay with the door you picked, or switch to the other door.
• Your objective is to decide on the best strategy for playing the game. Should you STAY with the door you originally chose? Should you SWITCH to the other unopened door? Or does it not make any difference in terms of your likelihood of winning the car?
• The bonus on the test will ask a question about the probability of winning with the 2 different choices: STAY or SWITCH.
• Two people: One person is Monty Hall and the other Person is the Contestant.
• Take 3 cards of the same color. Write Car on one of the cards and write Goat on the other 2 cards.
• Monty Hall shuffles the cards, looks at what is on each card and places the cards face down in front of the contestant.
• The contestant selects a "door" of his/her choice.
• Monty Hall turns over one of the other 2 cards that has a Goat.
• Contestant now can choose to STAY with 1st choice or SWITCH to the other "door" that has not been opened.
Your objective is to find P(winning) by STAYING and P(winning) by SWITCHING. Is there a better strategy or does it not make any difference? To answer, you need to play the game a large number of times and choose different strategies and then calculate the probability of winning with each strategy.

Added by Mark S.

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